A simple way to quickly determine the shape of a polar graph without the aid of a graphing calculator is to plot its points:
Quickly plotting points as show above allows a quick sketch of the graph to be drawn:
In general, however, all simple sine and cosine polar equations of the form r = acos(θ) or r = asin(θ) will be circles with a diameter of a that are either tangent to the polar axis and symmetric with respect to the line θ = π/2 (sine functions) or tangent to the line θ = π/2 and symmetric with respect to the polar axis (cosine functions).
There are three important types of symmetry to consider that can make graphing or predicting the shape of a polar function much easier.
Figure B: This is a polar function that is symmetric with respect to the polar axis (the cartesian x-axis). This can be tested for algebraically by replacing (r, θ) with either (r, -θ) or (-r, π - θ). If this substitution results in an equivalent equation, the equation is symmetric with respect to the polar axis.
Figure C: This is a polar function that is symmetric with respect to the pole (the origin). This can be tested for algebraically by replacing (r, θ) with either (r, π + θ) or (-r, θ). If this substitution results in an equivalent equation, the equation is symmetric with respect to the pole.
Special Polar Graphs:
Limaçons and cardioids with the form r = a ± bcos(θ) or r = a ± bsin(θ) where a > 0 and b > 0:
Figure A: This limaçon with the equation r = 1 + 2cos(θ) is looped because a/b < 1.
Figure B: This cardioid with the equation r = 1 + cos(θ) is heart-shaped because a/b = 1.
Figure C: This limaçon with the equation r = 3 + 2cos(θ) is dimpled because 1 < a/b < 2.
Figure D: This limaçon with the equation r = 4 + 2cos(θ) is convex because a/b ≥ 2.
Rose curves with the form r = acos(nθ) or r = asin(nθ) where n is an integer and a is the length of each petal:
Figure A: This rose curve with the equation r = cos(3θ) has 3 petals because n = 3. When rose curves have n as an odd number, the number of petals will equal n.
Figure B: This rose curve with the equation r = cos(4θ) has 8 petals because n = 4. When rose curves have n as an even number, the number of petals will equal 2n.
Figure C: This rose curve with the equation r = sin(5θ) has 5 petals because n = 5.
Figure D: This rose curve with the equation r = sin(2θ) has 4 petals because n = 2.
As a rule, rose curves are symmetric to the polar axis, the line θ = π/2, and the pole and have zeroes when r = 0 or θ = π/4, 3π/4.
Lemniscates with the form r2 = a2sin(2θ) or r2 = a2cos(2θ) where a is the length of each protrusion:
Figure A: This lemniscate with the equation r2 = sin(2θ) is mostly contained in the first and third quadrants due to the sine in its equation.
Figure B: This lemniscate with the equation r2 = cos(2θ) lies equally in all four quadrants due to the cosine in its equation.
As a rule, lemniscates are symmetric with respect to the pole and have zeroes when θ = 0, π/2.
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